10-15-2015, 08:17 AM
I have read some documents about Ram Air System, they say that increases power by mean of using cold air from atmosphere instead hot air from motor compartment.
I decided to do some numbers:
Calculated difference in amount of air between 86°F (30°C) and 194°F (90°C)
My Mustang is 351 in3 (5.75 lt), 8 cylinders
From general gas law, ideal gas law
PV = nRT
Where
P is atmosphere pressure = 1 atm
V is volume = 5.75 lt
n number of moles or grams
R is gas constant = 0.0821 atm lt / mol K
T is temperature in °K
For T1 of 30°C = 303°K
n1 = PV / RT = 1 * 5.75 / 0.0821 * 303 = 0.231 moles of air at 86°F
n2= PV / RT = 1 * 5.75 / 0.0821 * 363 = 0.193 moles of air at 194°F
Difference = 0.231 – 0.193 = 0.037 moles of air
Meaning a 16% less air at 194°F
So in that way we can run engine richer and have more power
What do you think?
Has somebody tested?
I decided to do some numbers:
Calculated difference in amount of air between 86°F (30°C) and 194°F (90°C)
My Mustang is 351 in3 (5.75 lt), 8 cylinders
From general gas law, ideal gas law
PV = nRT
Where
P is atmosphere pressure = 1 atm
V is volume = 5.75 lt
n number of moles or grams
R is gas constant = 0.0821 atm lt / mol K
T is temperature in °K
For T1 of 30°C = 303°K
n1 = PV / RT = 1 * 5.75 / 0.0821 * 303 = 0.231 moles of air at 86°F
n2= PV / RT = 1 * 5.75 / 0.0821 * 363 = 0.193 moles of air at 194°F
Difference = 0.231 – 0.193 = 0.037 moles of air
Meaning a 16% less air at 194°F
So in that way we can run engine richer and have more power
What do you think?
Has somebody tested?